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UNSW COMP1521 · 简单

COMP1521 2020T2 Q1 · MIPS基础翻译

COMP1521 2020T2 Q1 · 10 marks · MIPS 知识点: MIPS基础翻译(MASM-B) · 次: 整数算术 · 难度: 基础 Topic: MIPS basics · Source: https://cgi.cse.unsw.edu.au/~cs1521/26T1/resources/practice_exams.html

一句话 / Summary: 读2个整数输出其和


You have been given practice_q1.s , a MIPS assembler program that reads one number and then prints it.

Add code to practice_q1.s to make it equivalent to this C program:

// print the sum of two integers

#include <stdio.h>

int main ( void ) { int x , y ;

scanf ( "%d" , & x ); scanf ( "%d" , & y ); printf ( "%d \n " , x + y );

return 0 ; }

In other words, it should read 2 numbers and print their sum.

For example:

1521 mipsy practice_q1.s 5 8 13 1521 mipsy practice_q1.s 118 26 144 1521 mipsy practice_q1.s 42 42 84

No error checking is required.

Your program can assume its input always contains two integers, and only two integers.

You can assume the value of the expression can be represented as a signed 32 bit value. In other words, you can assume overflow/underflow does not occur.

Your solution must be in MIPS assembler only.

MIPS (mipsy)