COMP1521 2020T2 Q6 · 10 marks · C 知识点: 文件I/O（FILE） · 次: 数据表示ASCII · 难度: 基础 Topic: File I/O · Source: https://cgi.cse.unsw.edu.au/~cs1521/26T1/resources/practice_exams.html
一句话 / Summary: 统计文件中合法ASCII字节数
We need to count the number of ASCII bytes in files.
Write a C program, practice_q6.c , which takes a single filename as its argument, counts the number of bytes in the named file which are valid ASCII, and prints one line of output containing that count.
Assume a byte is valid ASCII iff it contains a value between 0 and 127 inclusive.
You must match the output format in the example below exactly.
dcc practice_q6.c -o practice_q6 echo hello world >file1 ./practice_q6 file1 file1 contains 12 ASCII bytes echo -e 'hello\xBAworld' >file2 ./practice_q6 file2 file2 contains 11 ASCII bytes echo -n -e '\x80\x81' >file3 ./practice_q6 file3 file3 contains 0 ASCII bytes
There is no supplied code for this question.
No error checking is required.
Your program can assume it is always given the name of a file.
Your solution must be in C only.
You are not permitted to run external programs. You are not permitted to use system, popen, posix_spawn, fork or exec.
🤖 Write a C program.
argv[1]is a filename (provided in the run workspace). Count the bytes in that file with value 0..127 and print exactly:<filename> contains <count> ASCII bytes.Fixture files are provided in the run workspace; reference outputs verified on the sandbox.